The Milwaukee Bucks have signed first-round draft pick Donte DiVincenzo to a rookie scale contract.

DiVincenzo, a 6-foot-5 guard, was selected by the Bucks with the 17th overall pick in the 2018 NBA Draft. He led Villanova to a national championship in April, earning 2018 Final Four Most Outstanding Player honors after scoring 31 points on 10-for-15 shooting in the national championship game and averaging 23.0 points, 6.5 rebounds and 3.0 assists per game at the Final Four.

The Delaware-native was named the BIG EAST’s Sixth Man of the Year for the 2017-18 season after he averaged 13.4 points, 4.8 rebounds, 3.5 assists and 1.1 steals per game as a redshirt sophomore while shooting 48.1 percent from the field and 40.1 percent from 3-point range

Less than 24 hours after Bucks forward D.J. Wilson posted a picture of DiVincenzo’s bank account showing $3.71 to the rookie’s name, DiVincenzo signed his first NBA contract. The 17th overall pick inked his deal on Tuesday, which is worth 120% of the rookie scale, coming in at about $5.3 million over his first two seasons. It also includes team options for DiVincenzo’s third and fourth seasons, which if picked up would bring his four-year total to approximately $13 million.

DiVincenzo, a 6-foot-5 guard out of Villanova, has yet to appear for the Bucks at the Las Vegas summer league. He missed the team’s first three games due to a right groin strain, though he has been able to participate in full-contact practices over the past few days.

His status for Milwaukee’s next game, which will likely be Wednesday as part of the summer-league tournament, remains unclear.

DiVincenzo appeared in 85 games, making 12 starts, during his three seasons with the Wildcats.